Answer
$4:32PM$
Work Step by Step
We know that
$\Delta t=\frac{\Delta t_{\circ}}{\sqrt{1-\frac{v^2}{c^2}}}$
We plug in the known values to obtain:
$\Delta t=\frac{2h}{\sqrt{1-\frac{(0.825c)^2}{c^2}}}$
$\Delta t=3.53h$
$\implies \Delta t=3 h\space 32min$
Now, the required time is $t=(1:00PM)+\Delta t$
$t=(1:00PM)+(3h\space 32min)$
$t=4:32PM$
