Answer
$1.01ms$
Work Step by Step
We can find the required difference of time between the earth clock and spaceship clock as follows:
$\Delta t_{Eart-spaceship }=\Delta t-\Delta t_{\circ}$
$\implies \Delta t_{Eart-spaceship }=\Delta t-\Delta t\sqrt{1-\frac{v^2}{c^2}}=\Delta t(1-\sqrt{1-v^2/c^2}) $
We plug in the known values to obtain:
$\implies \Delta t_{Eart-spaceship }=30.0d(1-\sqrt{1-(\frac{8350}{3.00\times 10^8})^2})(\frac{86,400}{1d})$
$ \Delta t_{Eart-spaceship }=0.00101s=1.01ms$
