Answer
$v=0.80c$
Work Step by Step
We know that
$v=c\sqrt{1-(\frac{\Delta t_{\circ}}{\Delta t})^2}$
We plug in the known values to obtain:
$v=c\sqrt{1-(\frac{0.15\times 10^{-9}s}{0.25\times 10^{-9}s})^2}$
$v=0.80c$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 29 - Relativity - Problems and Conceptual Exercises - Page 1041: 13
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