Answer
$0.68in$
Work Step by Step
We can find the required height of the sunflower as
$\Delta t=\frac{2.0in}{0.30in/day}=67days$
Now $\Delta t_{\circ}=\Delta t\sqrt{1-\frac{v^2}{c^2}}$
$\Delta t_{\circ}=(6.7d)\sqrt{1-(0.94)^2}=2.28d$
Now $h=(0.30in/d)(2.28d)$
$h=0.68in$
