Answer
$748m$
Work Step by Step
We know that
$d_{avg}=v\frac{\Delta t_{\circ}}{\sqrt{1-\frac{v^2}{c^2}}}$
We plug in the known values to obtain:
$d_{avg}=(0.750)(3.0\times 10^8)\frac{2.20\times 10^{-6}}{\sqrt{1-(0.75)^2}}=748m$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 29 - Relativity - Problems and Conceptual Exercises - Page 1041: 11
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