Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 942: 65

Answer

(a) $72^{\circ}$ (b) No

Work Step by Step

(a) We can find the value of $\theta$ as follows: $\theta=sin^{-1}[\frac{n_{glass}}{n_{air}}cos(sin^{-1}(\frac{n_{air}}{n_{glass}}))]$ We plug in the known values to obtain: $\theta=sin^{-1}[\frac{1.38}{1.00}cos(sin^{-1}(\frac{1.00}{1.38}))]$ This simplifies to: $\theta=72^{\circ}$ (b) We know that the angle of incidence at the vertical surface will be less as compared to the critical angle, if the value of $\theta$ is increased.
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