Answer
$1.41$
Work Step by Step
We can find the required minimum values of the index of refraction as
$n=\frac{n_{air}}{sin\theta _c}$
We plug in the known values to obtain:
$n=\frac{1.000}{sin45^{\circ}}$
$n=1.41$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 942: 62
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