Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 942: 54

Answer

$54^{\circ}$

Work Step by Step

We can find the angle of incidence as $n_{air}sin\theta_i=n_{ice}sin\theta_2$ This can be rearranged as: $\theta_i=sin^{-1}(\frac{n_{ice}}{n_{air}}sin\theta_2)$ $\theta_i=sin^{-1}(\frac{1.31}{1.00}sin38^{\circ})=54^{\circ}$
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