Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 942: 60

Answer

$3.61cm$

Work Step by Step

We can find the required height as follows: $H=W\sqrt{\frac{n_{water}^2-n_{air}^2}{4n_{air}^2-n_{water}^2}}$ We plug in the known values to obtain: $H=(6.2cm)\sqrt{\frac{(1.33)^2-(1.00)^2}{4(1.00)^2-(1.33)^2}}$ This simplifies to: $H=3.61cm$
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