Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 942: 57

Answer

$14.4ns$

Work Step by Step

We know that $t_{ice}=\frac{t_{ice}}{v_{ice}}$ We plug in the known values to obtain: $t_{ice}=\frac{0.38\times 1.31}{3\times 10^8}s$ $t_{ice}=1.6593ns$ and $t_{water}=\frac{d_{water}}{v_{water}}$ We plug in the known values to obtain: $t_{water}=\frac{2.87\times 1.33}{3\times 10^8}s$ $t_{water}=12.724ns$ Now $t_{total}=t_{ice}+t_{water}$ We plug in the known values to obtain: $t_{total}=1.6593+12.724=14.4ns$
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