Answer
$6.6\times 10^{-4}$
Work Step by Step
As $\frac{I_{puto}}{I_{Earth}}=\frac{\frac{P}{4\pi r_p^2}}{\frac{P}{4\pi r_E^2}}$
$\frac{I_{puto}}{I_{Earth}}=\frac{P}{4\pi r_p^2}\times \frac{4\pi r_E^2}{P}$
$\frac{I_{puto}}{I_{Earth}}=(\frac{r_E}{r_p})^2$
We plug in the known values to obtain:
$\frac{I_{puto}}{I_{Earth}}=(\frac{r}{39r})^2$
$\frac{I_{puto}}{I_{Earth}}=6.6\times 10^{-4}$
