Answer
$1.7\times 10^{-11}J$
Work Step by Step
As we know that
$\Delta t=\frac{1.0m}{c}=\frac{1.0m}{3.00\times 10^8}=3.33ns$
Now we can find the energy as
$E=P\Delta t$
We plug in the known values to obtain:
$E=5.0\times 10^{-3}(3.3\times 10^{-9})=1.7\times 10^{-11}J$