Answer
(a) $1.66\ KHz$
(b) $0.16\ MHz$
Work Step by Step
(a) We know that
$f_1-f_2=\frac{c}{\lambda_1}-\frac{c}{\lambda_2}$
We plug in the known values to obtain:
$f_1-f_2=(3.00\times 10^8)(\frac{1}{300.0}-\frac{1}{300.5})$
$f_1-f_2=1.66KHz$
(b) We know that
$f_1-f_2=\frac{c}{\lambda_1}-\frac{c}{\lambda_2}$
We plug in the known values to obtain:
$f_1-f_2=(3.00\times 10^8)(\frac{1}{30.0}-\frac{1}{30.5})$
$f_1-f_2=0.16MHz$
