Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 25 - Electromagnetic Waves - Problems and Conceptual Exercises - Page 902: 40

Answer

$670KHz$

Work Step by Step

The frequency of the station can be determined as $f=\frac{c}{\lambda}$ $\implies f=\frac{c}{4L}$ We plug in the known values to obtain: $f=\frac{3.00\times 10^8}{4(112)}=670KHz$
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