Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 25 - Electromagnetic Waves - Problems and Conceptual Exercises - Page 902: 41

Answer

(a) $0.23Km$ (b) $2.39m$

Work Step by Step

(a) We know that $\lambda_1-\lambda_2=\frac{c}{f_1}-\frac{c}{f_2}$ We plug in the known values to obtain: $\lambda_1-\lambda_2=(3.00\times 10^8)(\frac{1}{50\times 10^3}-\frac{1}{52\times 10^3})$ $\lambda_1-\lambda_2=0.23Km$ (b) We know that $\lambda_1-\lambda_2=\frac{c}{f_1}-\frac{c}{f_2}$ We plug in the known values to obtain: $\lambda_1-\lambda_2=(3.00\times 10^8)(\frac{1}{500\times 10^3}-\frac{1}{502\times 10^3})$ $\lambda_1-\lambda_2=2.39m$
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