Answer
(a) zero
(b) $(-9.57\times 10^{-9}T)\hat x+(2.07\times 10^{-8}T)\hat y$
Work Step by Step
(a) We know that the the magnetic field $(B^{\rightarrow})$ is perpendicular to the direction of propagation, hence the z-component is zero.
(b) We know that
$B=\frac{1}{c}[-E_y \hat x+E_x \hat y]$
We plug in the known values to obtain:
We plug in the known values to obtain:
$B=\frac{1}{3\times 10^8m/s}[(-2.87N/C)\hat x+(6.22N/C)\hat y]$
$\implies B=(-9.57\times 10^{-9}T)\hat x+(2.07\times 10^{-8}T)\hat y$
