Answer
$\Delta x=4.1\times 10^{16}m$
Work Step by Step
A light year is the distance light travels in 1 year. Since $$v=\frac{\Delta x}{\Delta t}$$ $\Delta x$ equals $$\Delta x=v\Delta t$$ Converting 4.3 years to seconds yields $$4.3yr \times \frac{365.25days}{1yr} \times \frac{24hr}{1day} \times \frac{60min}{1hr} \times \frac{60s}{1min}$$ $$=1.36\times 10^8s$$ Substituting known values of $\Delta t=1.36\times 10^8s$ and $v=c=3.00\times 10^8m/s$ yields a distance of $$\Delta x=(3.00\times 10^8m/s)(1.36\times 10^8s)$$ $$=4.1\times 10^{16}m$$
