Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 25 - Electromagnetic Waves - Problems and Conceptual Exercises - Page 900: 10

Answer

(a) $9.46\times 10^{12}Km$ (b) $1.00~light \space year/year$ (c) $0.98~4ft/ns$

Work Step by Step

(a) We can express 1 light year(ly) in Km as follows: $1~light \space year=(3\times 10^8m/s)(365days)(\frac{86400s}{day})$ $1~light \space year=9.46\times 10^{15}m=9.46\times 10^{12}Km$ (b) The speed of light in units of ly per year can be expressed as $1~light \space year=9.46\times 10^{15}m$ $\implies 1m=\frac{1}{9.46\times 10^{15}}light\space year$ We know that the speed of light is $c=3\times 10^8m/s$ $\implies c=\frac{(3\times 10^8)(\frac{1}{9.46\times 10^{15}})}{365\times 86400}$ $c=1.00~light \space year/year$ (c) The speed of light in feet per nanosecond can be expressed as $c=(3\times 10^8m/s)(\frac{1s}{10^9ns})(\frac{1ft}{0.3048m})$ $c=0.984~ft/ns$
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