Answer
$3.1\times 10^5\frac{m}{s}$
Work Step by Step
We can find the speed as
$v=\frac{F}{eBsin90^{\circ}}$
We plug in the known values to obtain:
$v=\frac{8.9\times 10^{-15}}{1.6\times 10^{-19}(0.18)}$
$v=3.1\times 10^5\frac{m}{s}$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 22 - Magnetism - Problems and Conceptual Exercises - Page 792: 8
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