Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 22 - Magnetism - Problems and Conceptual Exercises - Page 792: 20

Answer

$9.9mm$

Work Step by Step

We can find the radius of a proton's orbit as $r=\frac{mv}{eB}$ We plug in the known values to obtain: $r=\frac{(1.673\times 10^{-27})(6.27\times 10^5)}{(1.6\times 10^{-19})(0.66)}$ $r=9.9\times 10^{-3}m=9.9mm$
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