Answer
$9.9\times 10^8\frac{m}{s^2}$
Work Step by Step
We know that magnetic force is given as
$F=ma=evBsin90^{\circ}$
This can be rearranged as:
$a=\frac{evB}{m}$
We plug in the known values to obtain:
$a=\frac{(1.6\times 10^{-19})(6.5)(1.6)}{1.673\times 10^{-27}}$
$a=9.9\times 10^8\frac{m}{s^2}$
