Answer
$\vec{E}=(-4.3\times 10^3\frac{N}{C})\hat{y}$
Work Step by Step
We know that
$\vec{E}=vB(-\hat{y})$
We plug in the known value to obtain:
$\vec{E}=(4.5\times 10^3)(0.96)(-\hat{y})$
$\vec{E}=(-4.3\times 10^3\frac{N}{C})\hat{y}$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 22 - Magnetism - Problems and Conceptual Exercises - Page 792: 22
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