Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 22 - Magnetism - Problems and Conceptual Exercises - Page 792: 21

Answer

$2.5\frac{Km}{s}$

Work Step by Step

We can find the required speed as follows: $v=\frac{E}{B}$ We plug in the known values to obtain: $v=\frac{450}{0.18}$ $v=2.5\frac{Km}{s}$
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