Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 20 - Electric Potential and Electric Potential Energy - Problems and Conceptual Exercises - Page 723: 109

Answer

$(C). 1.6\times 10^{-6}J$

Work Step by Step

We know that $Energy=\frac{1}{2}CV^2$ We plug in the known values to obtain: $Energy=\frac{1}{2}\times 7.6\times 10^{-12}(650)^2$ $Energy=1.6\times 10^{-6}J$
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