Answer
B
Work Step by Step
The capacitance is given by
C = $\epsilon k\dfrac{A}{d}$ , where
$\epsilon$ = 8.8 X $10^{-12}$ F/m,
A = cross sectional area of the parallel plate capacitor = 1.8 $10^{-2} m^{-2}$,
d = distance between the plates = 2.0 m, and
k = dielectric constant = 95. So
C = 95 X 8.8 X $10^{-12} \times \dfrac{1.8 \times 10 ^{-2}}{2}$
C = 7.6 X $10^{-12}$.
