Answer
$C=4.2\times 10^{-6}F$
Work Step by Step
We can find the required capacitance as follows:
$C=\frac{\Delta q}{\Delta V}$
We plug in the known values to obtain:
$C=\frac{13.5\times 10^{-6}C}{3.25V}$
$C=4.2\times 10^{-6}F$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 20 - Electric Potential and Electric Potential Energy - Problems and Conceptual Exercises - Page 723: 104
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