Answer
$\eta=0.25$
Work Step by Step
We can find the engine's efficiency as follows:
$\eta=\frac{W}{Q_h}$
As given that $Q_h=4W$
$\implies \eta=\frac{W}{4W}$
$\eta=\frac{1}{4}=0.25$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 18 - The Laws of Thermodynamics - Problems and Conceptual Exercises - Page 648: 78
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