Answer
$0.07Kg $
Work Step by Step
We know that
$\Delta S=\frac{Q}{T}$
We plug in the known values to obtain:
$87=\frac{Q}{273}$
$\implies Q=2375J=23.75KJ$
As latent heat of fusion of water is $334\frac{KJ}{Kg}$
Thus, $\frac{23.75}{334}=0.07Kg $ of ice melts.
