Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 16 - Temperature and Heat - Problems and Conceptual Exercises - Page 566: 3

Answer

(a) $37^{\circ}C$ (b) $310.2K$

Work Step by Step

(a) We know that $T_C=\frac{5}{9}(T_F-32^{\circ}F)$ We plug in the known values to obtain: $T_C=\frac{5}{9}(98.6^{\circ }F-32^{\circ}F)$ $T_C=37^{\circ}C$ (b) As $T_K=T_C+273.15K$ We plug in the known values to obtain: $T_K=37K+273.15K=310.2K$
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