Answer
$T_F=-458^{\circ}F$
Work Step by Step
We know that
$T_F=\frac{9}{5}(T_K-273.15)+32$
We plug in the known values to obtain:
$T_F=\frac{9}{5}(1.0-273.15)+32$
$T_F=-458^{\circ}F$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 16 - Temperature and Heat - Problems and Conceptual Exercises - Page 566: 4
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