Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 16 - Temperature and Heat - Problems and Conceptual Exercises - Page 566: 17

Answer

$\Delta L=1.6m$

Work Step by Step

We know that $\Delta L=\alpha L_{\circ}\Delta T$ We plug in the known values to obtain: $\Delta L=1.2\times 10^{-5}(3910)(30.00-(-5.00))$ $\Delta L=1.6\ m$
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