Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 16 - Temperature and Heat - Problems and Conceptual Exercises - Page 566: 2

Answer

$T_C=2482\ C^{\circ} \approx 2500\ C^{\circ}$

Work Step by Step

The given temperature can be converted in Celsius as follows: $T_C=\frac{5}{9}(T_F^{\circ}-32F^{\circ})$ $T_C=\frac{5}{9}(4500F^{\circ}-32F^{\circ})$ $T_C=2482\ C^{\circ} \approx 2500\ C^{\circ}$
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