Answer
(a) $19.4\frac{J}{s}$
(b) $0.16C^{\circ}$
Work Step by Step
(a) We know that
$\frac{Q}{t}=kA(\frac{\Delta T}{L})$
We plug in the known values to obtain:
$\frac{Q}{t}=(0.0234)(0.725)(\frac{20.0}{0.0175})$
$\frac{Q}{t}=19.4\frac{J}{s}$
(b) As $ \Delta T=\frac{Q}{t}(\frac{L}{kA})$
We plug in the known values to obtain:
$\Delta T=19.4\times (\frac{0.0050}{0.84\times (0.725)})=0.16C^{\circ}$
