Answer
The rate of heat transfer is reduced by a factor of 36.
Work Step by Step
We know that
$\frac{Q}{t}=KA\frac{\Delta T}{L}$
We plug in the known values to obtain:
$\frac{Q}{t}=(0.0234)(0.84)(0.36)(\frac{15}{0.0035})(\frac{60s}{min})=1.8KJ/min$
Now we can compare the two rates of heat transfer as:
$\frac{(Q/t)_{glass}}{(Q/t)_{air}}=\frac{65}{1.8}=36$
Thus, the rate of heat transfer is reduced by a factor of 36.
