Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 16 - Temperature and Heat - Problems and Conceptual Exercises - Page 368: 54

Answer

(a) $0.800m$ (b) decreased by a factor of 2.

Work Step by Step

(a) We know that $L=\frac{A\Delta T(K_{Aluminum+K_{St.steel}})}{H}$ We plug in the known values to obtain: $L=\frac{\pi(\frac{3.50\times 10^{-2}m}{2})^2(98K)(217W/m.K)+(16.3W/m.K)}{27.5J/s}$ $\implies L=0.800m$ (b) We know that $L\propto \frac{1}{H}$ This relation shows that if the length of the rods is doubled then the rate of heat flow is decreased by a factor of $2$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.