Answer
$P=1.03\times 10^5Pa$
Work Step by Step
We can find the required pressure as follows:
$P_1=P_{at}+\rho gh$
$P_1=1.013\times 10^5+(920)(9.81)(0.072)$
$P_1=1.0195\times 10^5Pa$
Now $P=P_1+\rho_{water}+gh_{water}$
We plug in the known values to obtain:
$P=1.0195\times 10^5+(1000)(9.81)(0.12)$
$P=1.03\times 10^5Pa$
