Answer
$\mathrm{a}.$ greater
$\mathrm{b}.$ equal
Work Step by Step
The density, $\rho$, of a material is its mass M per volume V:
$\rho=\mathrm{M}/\mathrm{V} \qquad $15-1
If the pressure at one point in a fluid is $\mathrm{P}_{1}$, the pressure at a depth $\mathrm{h}$ below that point is
$\mathrm{P}_{2}=\mathrm{P}_{1}+\rho \mathrm{g}\mathrm{h} \qquad $15-7
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$\mathrm{a}.$
$\mathrm{M}=\rho \mathrm{V},$
so the greater mass (and weight) of water will be in the glass with greater volume. Glass 1 has a larger radius, the heights are the the same. The weight of the water in glass 1 is greater.
$\mathrm{b}.$
The depth is the same in both glasses, so $\Delta P=\rho gh$ (by 15-7) for both. That is, the pressure is the same at the bottom of each glass.
