Answer
(a) $995m$
(b) greater than
Work Step by Step
(a) We know that
$h=\frac{P-P_{atm}}{\rho_w g}$
We plug in the known values to obtain:
$h=\frac{(10N/mm^2)(\frac{10^3mm}{m})^2}{(1025)(9.81)}$
$h=995m$
(b) We know that the sea water is denser compared to fresh water. Hence, the maximum depth in fresh water is greater than in sea water.
