Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 15 - Fluids - Problems and Conceptual Exercises - Page 531: 22

Answer

a) $P=1.45\times 10^5Pa$ b) $P=1.54\times 10^5Pa$ c) Because the water pressure increases with depth

Work Step by Step

(a) We know that $P=P_{at}+\rho gh$ We plug in the known values to obtain: $P=1.01\times 10^5+(1000)(9.81)(4.5)$ $P=1.45\times 10^5Pa$ (b) We know that $P=P_{at}+\rho gh$ We plug in the known values to obtain: $P=1.01\times 10^5+(1000)(9.81)(5.5)$ $P=1.54\times 10^5Pa$ (c) We know that the water pressure increases with depth, hence the bands near the bottom are more closely spaced to provide enough support.
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