Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 15 - Fluids - Problems and Conceptual Exercises - Page 531: 17

Answer

(a) $P=98.2KPa$ (b) $h=10.0m$

Work Step by Step

(a) We know that $P=\rho gh$ We plug in the known values to obtain: $P=(13600)(9.81)(0.736)$ $P=98.2KPa$ (b) As We know that $P_2=P_1+\rho gh$ This can be rearranged as: $h=\frac{P_2-P_1}{\rho g}$ We plug in the known values to obtain: $h=\frac{9.82\times 10^4-0}{1000(9.81)}$ $h=10.0m$
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