Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 14 - Waves and Sound - Problems and Conceptual Exercises - Page 493: 36

Answer

$1.67Km$

Work Step by Step

We know that $\frac{I_2}{I_1}=\frac{P/4\pi r_2^2}{P/4\pi r_1^2}$ This simplifies to: $\frac{I_2}{I_1}=(\frac{r_1}{r_2})^2$ This can be rearrangned as: $r_2=r_1\sqrt{\frac{I_1}{I_2}}$ We plug in the known values to obtain: $r_2=(1.0)\sqrt{\frac{2.80\times 10^{-6}}{10^{-12}}}=1.67Km$
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