Answer
$I=1.6\times 10^{-3}W/m^2$
Work Step by Step
To find the sound level, use the equation $$\beta=10log(\frac{I}{I_o})$$ Solving for $I$ yields $$\frac{\beta}{10}=log(\frac{I}{I_o})$$ $$I=I_o \times 10^{\frac{\beta}{10}}$$ Substituting known values of the threshold of hearing $I_o=10^{-12} W/m^2$ and $\beta=92dB$ yields an intensity of $$I=10^{-12} W/m^2 \times 10^{\frac{92}{10}}=1.6\times 10^{-3}W/m^2$$
