Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 14 - Waves and Sound - Problems and Conceptual Exercises - Page 493: 29

Answer

(a) $0.807m$ (b) decrease (c) $0.722m$

Work Step by Step

(a) We can find the wavelength as $\lambda=\frac{v}{f}$ We plug in the known values to obtain: $\lambda=\frac{343}{425}=0.807m$ (b) We know that the frequency and wavelength are inversely proportional. Thus, if the frequency is increased then the wavelength will decrease. (c) The wavelength can be calculated as $\lambda=\frac{v}{f}$ $\implies \lambda=\frac{343}{465}=0.722m$
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