Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 14 - Waves and Sound - Problems and Conceptual Exercises - Page 493: 32

Answer

By $\frac{1}{4}$

Work Step by Step

The intensity of sound is equal to $$I=\frac{P}{A}=\frac{P}{4\pi R^2}$$ Since $R'=2R$, the new intensity becomes $$I'=\frac{P}{4\pi (2R)^2}=\frac{P}{16\pi R^2}=\frac{1}{4}I$$ This means that the intensity is multiplied by $\frac{1}{4}$.
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