Answer
$566Hz$
Work Step by Step
We know that
$f^{\prime}=(\frac{1+u_{\circ}/v}{1-u_s/v})f$
We plug in the known values to obtain:
$f^{\prime}=(\frac{1+(13.0/343)}{1-(27.0/343)})(502)$
$f^{\prime}=566Hz$
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