Answer
a) $\alpha=4.12\times 10^2\frac{rad}{s^2}$
b) $\omega=6.2\times 10^2\frac{rad}{s}$
Work Step by Step
(a) We know that
$\alpha =\frac{a}{r}$
We plug in the known values to obtain:
$\alpha=\frac{3.3}{\frac{1}{2}(0.016)}=4.12\times 10^2\frac{rad}{s^2}$
(b) As $\omega=\omega_{\circ}+\alpha t$
$\omega=0+\frac{a}{r}t$
$\omega=\frac{3.3}{\frac{1}{2}(0.016)}(1.5)=6.2\times 10^2\frac{rad}{s}$
