Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 329: 102

Answer

a) $\omega_{max}=2100\frac{rad}{s}$ b) $v=21\frac{m}{s}$

Work Step by Step

(a) We know that $\omega_{max}=2\omega_{avg}$ $\omega_{max}=2\frac{\Delta \theta}{\Delta t}$ We plug in the known values to obtain: $\omega_{max}=2(\frac{\frac{100\pi}{3rad}}{1.0})=2100\frac{rad}{s}$ (b) We know that $v=r\omega$ We plug in the known values to obtain: $v=(0.010)(2100\frac{rad}{s})$ $v=21\frac{m}{s}$
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