Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 329: 94

$0.20\frac{m}{s}$

We know that $\omega=\frac{\Delta \theta}{\Delta t}$ $\omega=\frac{\Delta \theta}{\sqrt{\frac{2y_{\circ}}{g}}}$ We also know that $v=r\omega$ $\implies v=r\frac{\Delta \theta}{\sqrt{\frac{2y_{\circ}}{g}}}$ We plug in the known values to obtain: $v=(0.032)\frac{0.37\times 2\pi}{2(0.66)(9.81)}=0.20\frac{m}{s}$