Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 329: 100

Answer

$\omega=1.7\times 10^2\frac{rad}{s}$

Work Step by Step

We know that $U_i+K_i=U_f+K_f$ $\implies 0+\frac{1}{2}I\omega^2=mgh+0$ This simplifies to: $\omega=\sqrt{\frac{2mgh}{I}}$ We plug in the known values to obtain: $\omega=\sqrt{\frac{2(0.11)(9.81)(1.0)}{7.4\times 10^{-5}}}$ $\omega=1.7\times 10^2\frac{rad}{s}$
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