Answer
$\omega=1.7\times 10^2\frac{rad}{s}$
Work Step by Step
We know that
$U_i+K_i=U_f+K_f$
$\implies 0+\frac{1}{2}I\omega^2=mgh+0$
This simplifies to:
$\omega=\sqrt{\frac{2mgh}{I}}$
We plug in the known values to obtain:
$\omega=\sqrt{\frac{2(0.11)(9.81)(1.0)}{7.4\times 10^{-5}}}$
$\omega=1.7\times 10^2\frac{rad}{s}$