Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 328: 86

Answer

$190\frac{m}{s}$

Work Step by Step

As we know that $\Delta t=\frac{\Delta \theta}{\omega}$ $\Delta t=\frac{\frac{1}{16}}{5.40}=0.0012s=1.2ms$ Now $v=\frac{\Delta x}{\Delta t}$ We plug in the known values to obtain: $v=\frac{0.645-0.420}{0.0012}=190\frac{m}{s}$
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